(Y+1)^2=-8(x-4)

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Solution for (Y+1)^2=-8(x-4) equation: 



(+1)^2=-8(Y-4)

We move all terms to the left:

(+1)^2-(-8(Y-4))=0

We add all the numbers together, and all the variables

-(-8(Y-4))+1^2=0

We add all the numbers together, and all the variables

-(-8(Y-4))+1=0



We calculate terms in parentheses: -(-8(Y-4)), so:

-8(Y-4)

We multiply parentheses

-8Y+32

Back to the equation:

-(-8Y+32)



We get rid of parentheses

8Y-32+1=0

We add all the numbers together, and all the variables

8Y-31=0

We move all terms containing Y to the left, all other terms to the right

8Y=31

Y=31/8

Y=3+7/8

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